Enter your username:
Do you want to login or register?
  • Forgot your password?

    Login / Register




    Results 1 to 10 of 10

    Hybrid View

    1. #1
      Join Date
      Oct 2007
      Location
      Newark DE
      Posts
      238
      Country Flag: United States

      Sway bar formula?

      As of now I have a 1.25" solid bar that I like, but I want better tuning options. Been looking at hollow adjustable sway bars but I don't know the formula to figure out the stiffness. Is the formula different for solid vs. hollow?



    2. #2
      Join Date
      Nov 2002
      Location
      state of confusion
      Posts
      1,499
      Country Flag: United States
      For all practical purposes, the stiffness of a solid bar is a function of

      [Outside diameter]^4

      while that of a tubular bar is

      [Outside diameter]^4 - [Inside diameter]^4


      There's an approximate formula in Fred Puhn's softcover book "How To Make Your Car Handle". Maybe somebody who has a way of hosting scanned pics can put it up for you. One caution - I think that formula computes the stiffness of the bar from one endlink to the other (as opposed to being from one endlink to the midpoint, which would be twice as stiff, and perhaps more useful).


      Norm
      '08 GT coupe, 5M, suspension unstockish (the occasional track toy)
      '19 WRX, Turbo-H4/6M (the family sedan . . . seriously)
      Gone but not forgotten dep't:
      '01 Maxima 20AE 5M, '10 LGT 6M, '95 626, V6/5M; '79 Malibu, V8/4M-5M; '87 Maxima, V6/5M; '72 Pinto, I4/4M; '64 Dodge V8/3A

    3. #3
      Join Date
      Oct 2007
      Location
      Newark DE
      Posts
      238
      Country Flag: United States
      Thank you Norm. I have the book some where but I don't remember it having a separate formula for a hollow bar.

      I see you are near Philly, what town? I'm from Laurel Springs originally.

    4. #4
      Join Date
      Nov 2002
      Location
      state of confusion
      Posts
      1,499
      Country Flag: United States
      It doesn't, so the simplest way around it is to run the numbers twice (once using OD and once using ID) and take the difference between the results. Or use (OD^4 - ID^4) in place of D^4 in the numerator, as it amounts to the same thing.

      Or you can dig out tables of beam formulas and section properties and derive your own formula that works up the result directly.


      They used to call this place Delaware Twp (but that was before the water tower was built )


      Norm
      '08 GT coupe, 5M, suspension unstockish (the occasional track toy)
      '19 WRX, Turbo-H4/6M (the family sedan . . . seriously)
      Gone but not forgotten dep't:
      '01 Maxima 20AE 5M, '10 LGT 6M, '95 626, V6/5M; '79 Malibu, V8/4M-5M; '87 Maxima, V6/5M; '72 Pinto, I4/4M; '64 Dodge V8/3A

    5. #5
      Join Date
      Oct 2007
      Location
      Newark DE
      Posts
      238
      Country Flag: United States
      Quote Originally Posted by Norm Peterson


      They used to call this place Delaware Twp (but that was before the water tower was built )


      Norm
      BTW is that Camden County? If so I know where your at...haha

    6. #6
      Join Date
      Jun 2001
      Location
      Newbury Park, CA
      Posts
      5,839
      Country Flag: United States
      Assuming same materials and length, the D^4 - d^4 works for hollow bars. If different materials and end conditions exist then the full formula must be used.

      I'll get it tonight. It's a standard torsion formula.
      VaporWorx. We Give You Gas http://www.vaporworx.com

    7. #7
      Join Date
      Nov 2002
      Location
      state of confusion
      Posts
      1,499
      Country Flag: United States
      Torsion in the center section (Puhn's A^2*B term)
      Arm bending (the C^3 term in Puhn's formula)

      A few other, typically minor considerations
      Bending in the center section (more important in tubular bars, and mostly associated with thinnish OE-style front bars)
      Shear
      Center section overhanging its chassis bushings/bearings (which cannot be precisely at the bend/joint, and may be several inches inboard)

      Considering only torsion can easily result in overestimating the stiffness by as much as 20% unless the arms are separate pieces and particularly rigid. Torsion plus arm bending is usually good to within 5% or so.

      Bushing and endlink stiffnesses also play a part as yet other springs in series with the bar itself, but that's almost a whole 'nother topic in itself. Mentioned because it's sort of related and does explain why you can always feel the difference after swapping poly-bushed endlinks in for the OE rubber pieces.


      Norm
      '08 GT coupe, 5M, suspension unstockish (the occasional track toy)
      '19 WRX, Turbo-H4/6M (the family sedan . . . seriously)
      Gone but not forgotten dep't:
      '01 Maxima 20AE 5M, '10 LGT 6M, '95 626, V6/5M; '79 Malibu, V8/4M-5M; '87 Maxima, V6/5M; '72 Pinto, I4/4M; '64 Dodge V8/3A

    8. #8
      Join Date
      Oct 2007
      Location
      Newark DE
      Posts
      238
      Country Flag: United States
      I don't need the exact stiffness, maybe within 10%. I want to base line the current setup and us that as a mid point in the adjustment range of the new setup.

      As of now it has poly bushings and end links. With the adjustable bar it will have rod ends for the end links and pillow blocks instead of bushings. The seem like a good alternative to solid mounts in a heavily street driven application IMO.

      Can you write the formulas in "stupid" form. I don't understand what "^" represents.

    9. #9
      Join Date
      Nov 2002
      Location
      state of confusion
      Posts
      1,499
      Country Flag: United States
      Quote Originally Posted by 87wildside
      Can you write the formulas in "stupid" form. I don't understand what "^" represents.
      I'm not sure I can do that in this particular situation. The " ^ " character is used to indicate exponent, so " ^3 " means "cubed" and " ^4 " means "raised to the 4th power". So if D is 1.25", D^4 is 2.44 in^4.


      87 - Yup.


      Norm
      '08 GT coupe, 5M, suspension unstockish (the occasional track toy)
      '19 WRX, Turbo-H4/6M (the family sedan . . . seriously)
      Gone but not forgotten dep't:
      '01 Maxima 20AE 5M, '10 LGT 6M, '95 626, V6/5M; '79 Malibu, V8/4M-5M; '87 Maxima, V6/5M; '72 Pinto, I4/4M; '64 Dodge V8/3A

    10. #10
      Join Date
      Oct 2007
      Location
      Newark DE
      Posts
      238
      Country Flag: United States
      OK. That's what I thought but wasn't sure. Thanks.




    Advertise on Pro-Touring.com