Results 21 to 25 of 25
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09-20-2004 #21
hi I'm new. As for the 3g being attainable, I think the hardest part is the lateral g. I did some engineerng math and if decel and accel are constant. It takes about 1.9 seconds to accel to 60ft from 0 mph to hit 1g, takes less than 122 feet to decel from 60mph to 0mph to hit 1g decel and for lateral one must attain a minumum of 38.5 mph going round a 200 foot diameter skidpad.
so With good tires and brakes I think a modified car can hit the accel and decel. Lateral usually takes really sticky tires and good suspension.
My take anyway.
Alcino
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09-20-2004 #22would you mind telling me the formula on that one?
Originally Posted by alcino
09-20-2004 #23Lateral Acceleration (g) = 0.067 * MPH^2 / Radius (in feet)
You have to take track width into account for radius. Normally, this is done by going inside the circle on CW direction and outside the circle on CCW direction, then take the average.
09-20-2004 #24For the formula I used A = V^2 /R
But the above works as well.
I wonder if the local Solo2 SCCA clubs are willing to hold a 3g test day? Has there ever been an event like this? I think that would be fun to see what she gots.
Alcino
09-21-2004 #25Yup, they are the same equation. 0.067 is just a conversion factor.
Lateral accel. in G = (accel. in ft/s^2)/(32.174 ft/s^2) = [(speed in miles/hr)^2 * (5280 ft/mile)^2/(3600 sec/hr)^2] / Radius in ft.
therefore conversion factor is...
5280^2 / 3600^2 *32.174 = 0.0669 ~ 0.067
Art Morrison will try to get close to 3G in his '60 Corvette project.



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