calculating brake force???

[ks71z28]

I have experamented with several systems on 2nd gen Camaros

1- 12" rotor and 2.75 single piston Wilwood caliper, 1" master

2- 12.8" rotor. 1.69, 1.69" 2 piston PBR caliper. .87" Master

3- 12.9" rotor. 1.62, 1.12, 1.12" 6 piston Wilwood. .87" master

4- 12.9" rotor. 1.75, 1.75" wilwood 4 piston, .87 master

By my calculations, system 4 is the strongest brake torque, 2 is second, 1 is third, and 3 is the worst.

#3 is Wilwoods 6 piston kit for the second gen, 1st gen, and corvette. So why would it be an "upgrade" I am trying to work out some details in theory before bitting the bullet.

My concerns

4 piston with 2.75 bore, has more clamping force than a 6 piston with 1.62, 1.12, 1.12 bores- why 6 pistons???

2 piston floating caliper has same clamping force as 4 piston, and more than 6 piston fixed caliper. Is a fixed caliper going to somehow create more clamping force in its design??

Sorry if this seems like babble, but I am not buying into some of these kits out there that are "Bike Brake" set ups that mathmatically any better than a stock set up. the calculators I used measure caliper force and torque at the wheel.

I would appreciate some input. I went from set up #1 with power brakes, to set up #2 with manual brakes, and now couldn't lock the brakes with both legs, and now considering set ups #3 and #4.

thanks